Question

solve the system by either elimination or substitution
3x-5y=21
2x+y=1
A.2,-3
B.2,3
C.-2,-1
D.-2,1
My guess is c

Answer 1

you could multiply the second equation by 5 and
then add the equations together afterwards
thus eliminating the y

Answer 2

what would the second equation look like after multiplying it by 5?

Answer 3

\[2x+y=1 \\ 5(2x+y)=5(1) \\ \text{ use distributive property on the left } \\ 5(2x+y)=5\]

Answer 4

remember that is a(b+c)=ab+ac
this is distributive property

Answer 5

i got 10x+5y=5

Answer 6

ok add the equations now