Question

Evaluate and tell if it is extraneous or not. x^2-6x+13=0

Answer 1

@geny55

Answer 2

Step 1 :

Raise x to the 2nd power

Answer 3

factor?

Answer 4

this is the Equation at the end of step 1 :

(x2 - 6x) + 13 = 0

Answer 5

Step 2 :

Simplify x2-6x + 13

Answer 6

3+ or - 2i

Answer 7

Equation at the end of step 2 :

x2 - 6x + 13 = 0

Answer 8

ok:)

Answer 9

so what would the answer be? bc i factored it

Answer 10

Simplifying
x2 + 6x + 13 = 0

Answer 11

Reorder the terms:
13 + 6x + x2 = 0

Solving
13 + 6x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-13' to each side of the equation.
13 + 6x + -13 + x2 = 0 + -13

Reorder the terms:
13 + -13 + 6x + x2 = 0 + -13

Combine like terms: 13 + -13 = 0
0 + 6x + x2 = 0 + -13
6x + x2 = 0 + -13

Combine like terms: 0 + -13 = -13
6x + x2 = -13

The x term is 6x. Take half its coefficient (3).
Square it (9) and add it to both sides.

Add '9' to each side of the equation.
6x + 9 + x2 = -13 + 9

Reorder the terms:
9 + 6x + x2 = -13 + 9

Combine like terms: -13 + 9 = -4
9 + 6x + x2 = -4

Factor a perfect square on the left side:
(x + 3)(x + 3) = -4

Can't calculate square root of the right side.

The solution to this equation could not be determined.