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Find S12 for the series 1 + 2 + 4 + 8 +.. i got 2048
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@Michele_Laino am i right
here we have a geometric series, whose first term is a1=1 and constant q= 2
okay
so, we can apply this formula: \[\Large {S_{12}} = {a_1}\frac{{1 - {q^{12}}}}{{1 - q}}\]
okay
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after a substitution, i get this: \[\Large {S_{12}} = {a_1}\frac{{1 - {q^{12}}}}{{1 - q}} = 1 \cdot \frac{{1 - {2^{12}}}}{{1 - 2}} = ...?\]
-4097
I got 4095
nvm ur right, typo sorry lol
so its 4095
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yes!
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