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if your question \[x^{4\sqrt{x}}\]
is*
can you post a picture of the question here?
ok. firstly, rational expo form is \[a^{m/n} \rightarrow \sqrt[n]{a^m}\] do you get this so far?
\[\sqrt{x} = x^{1/2}\] and \[\sqrt[4]{x} = x^{1/4}\] do you get this?
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So, by exponential law of multiplication. we get \[x^{1/2+1/4} \rightarrow x^{3/4} \rightarrow \sqrt[4]{x^3}\]
the squre root is 1/2 in rational form
yes x^{3/4}
np anything else?
you can always ask question here to https://www.facebook.com/pages/Delta-Epsilon/1481351345517305?ref=aymt_homepage_panel
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