URGENT! Write an equation in point-slope form for the line through the given point with the given slope. (10,-9); m=-2
You need an equation in this form: \(\large y = mx + b\)
okay so do you know y=mx=b
y=mx+b
Let m = the given slope, so m = -2. We now have: \(\large y = -2x + b\)
sorry ;/
*point slope* \[\huge\rm y-y_1=m(x-x_1)\]
i jst came here to smile :)
Now put the x and y of your point in the x and y of our equation and solve for b. \(\large y = -2x + b\) \(\large -9 = -2(10) + b\) \(\large -9 = -20 + b\) \(\large 11 = b\) Now that we know b = 11, substitute 11 for b. \(\large y = -2x + b\) \(\large y = -2 x + 11\)
@Nnesha is correct above. They ask for point-slope, not slope-intercept. \(\large y - y_1 = m(x - x_1) \) \(\large y - (-9) = -2(x - 10)\)
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