For f(x) = x2 and g(x) = (x − 5)2, in which direction and by how many units should f(x) be shifted to obtain g(x)? Up 5 units Down 5 units Left 5 units Right 5 units SOMEONE HELP FAN AND MEDAL
okay so is that x squared
or just 2x
yeah squared
okay
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okay, so we have \[x ^{2}\] and \[x ^{2}-10x+25\]
ok so what does that mean?
from your answer choices, how are you going to get the first part to the second
idk, idk how to do this lol
wait, you what would be easier? lol scratch everything i said
so
ok :)
since both expressions are squared, we can square root both of them
you better live it g(x)=(x-5)^2 to see what shift needed
meaning we just have x and x-5
leave*
so, since you are subtracting, you are either going down or to the left
ok
i wouldnt leave it if i were you actually
ok go on please :)
ok let's how you gonna do it
see*
ok
well we already have x and x-5, because we square rooted, and you want him to leave it as squared, thats totally fine and you can help him
that's not a square root? where did you see any square root?
Okay lets consider a function f(x)=x^2 we call it parent function
ok
if we want to move the graph of that function f(x) to right some units away i will use b units here we just do the following \(f(x-b)=(x-b)^2\) that is b units to the right away ffrom f(x) let's give this new function a name h(x) so that \(h(x)=f(x-b)=(x-b)^2\)
following ?
now we want to move f(x) to obtain g(x) look at the g(x) and tell me what do you need to do to move f such that it becomes g
earth to you, hello, are you there?
yes im following
so according to what i just said what can we do to shift f to get g?
just compare what i did with what we have?
i honestly dont know im guessing 5 down or to the left
why down and left in my explanation i have not spelled at all any thing about down or left shifting
i only i explained one thing; that is shift a curve x^2 to right by a b units to get (x-b)^2
so basically to get from f(x)=x^2 to g(x)=(x-5)^2 we need to shift f(x) 5 units to the right
can you just tell me the answer and explain cause you're not helping that well :)
oh thanks
so d?
it is not me who is not helping it is you who don't want to be helped haha
i was deriving you to the answer but you seem not to pay attention
yes it is D
ok thanks can you help on like 4 more???
are u sure?
@xapproachesinfinity
trillion times sure! and no i can't if you don't have much interest to work the problem
no i will i promise @xapproachesinfinity
What is the domain of the following parabola? u-shaped graph that opens up with a vertex of 2, negative 3 All real numbers x ≥ 1 x ≤ 2 y ≥ −3
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help me @xapproachesinfinity
all sort of parabolas have the domain all real number no matter what it is
if we speak about co-domain (range) then the story is different
so its all real numbers im assuming?wait no
if you want the reason just think is there any number that cause a function of the sort f(x)=ax^2+bx+c does not exist i mean is there a point where that graph has discontinuity
the answer is no, all real numbers are acceptable in the machine of parabolas
so no all real numbers
im saying all real numbers and you are saying no all real numbers
pay a bit of attention dear :)
ohhh ok it is all real numbers i apologize
no problem
The quadratic functions f(x) and g(x) are described as follows: f(x) = −8x2 + 7 x g(x) 0 0 1 2 2 6 3 2 4 0 Which of the following statements best compares the maximum value of the 2 functions? It is the same for both functions. f(x) has a greater maximum value than g(x). g(x) has a greater maximum value than f(x). The maximum values cannot be determined can u help on like 3 more? plz @xapproachesinfinity
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