Question

Find x and y so that the equation is true

(x+y)^2 + (x+y)^2 = (x^2 + 2xy + y^2)

Answer 1

it can be any number for x and y as long as the equation is true in the end

Answer 2

are you sure that's the right equation? $$x^2+2xy+y^2=(x+y)^2$$so your question is equivalent to $$(x+y)^2+(x+y)^2=(x+y)^2\\\implies (x+y)^2=0\\\implies x=-y,y\in\mathbb{R}$$

Answer 3

it is an equation I had to make. If you wait i can give you the list of equations

Answer 4

Column A
(x-y)
(x+y)
(y+x)
(y-x)

Column B
(x^2 + 2xy + y^2)
(x^2 - 2xy + y^2)
(ax+b)
(cy+d)

Answer 5

there you go @oldrin.bataku

Answer 6

if you could figure out a polynomial identity that works by combining 1 thing from column A and one from column B.

Answer 7

x=0 and y=0

Answer 8

besides 0 and 0 :/

Answer 9

@raesal