A solution is made by dissolving 10.20 grams of glucose (C6H12O6) in 355 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m? Show all of the work needed to solve this problem.

Question

vocaloid · Answer

to find freezing point depression, we will use the formula

deltaT = (i)(Kf)(m)

where i is the van't Hoff factor (in this case, we're using glucose so i = 1)
Kf is the freezing point constant (given: Kf = -1.86)
and m is the molality of the solution

vocaloid · Answer

we have i and Kf, so all we need to find is m

m = molality = moles of glucose/kg of water

so, we need to convert 10.20 g of glucose to moles, by dividing 355 by the molar mass of glucose

also, we need to convert 355g of water to kg by dividing by 1000 (since 1000g = 1kg)

vocaloid · Answer

whatever you get for deltaT will be your final answer

tag me if you are unclear