Question

((a-1)/8) - (3(a-4)/10) = ((2a+4)/5)

help please

Answer 1

solve for a

Answer 2

\[\frac{ a-1 }{ 8 }-\frac{ 3(a-4) }{ 10 }=\frac{ 2a+4 }{ 5 }\]
Your denominators are 8, 10 and 5. What's the smallest number that is divisible by all 3 (lcd)?

Answer 3

80?

Answer 4

80's not the smallest, but it will still work :)
You need to multiply each of the fractions by 80 so the denominators will cancel when you reduce.
\[\frac{ 80(a-1) }{ 8 }-\frac{ (80)(3)(a-4) }{ 10 }=\frac{ 80(2a+4) }{ 5 }\]

Answer 5

i got 2.215

Answer 6

as my final answer

Answer 7

that's not what I got. Can you put up what you did?

Answer 8

i got -65/23 is that right? @peachpi

Answer 9

??

Answer 10

no. the 23 is right, so everything you did with the a is good. check your addition/subtraction with the constants

Answer 11

11?

Answer 12

yes

Answer 13

11/23

Answer 14

can u show me how you got that