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((a-1)/8) - (3(a-4)/10) = ((2a+4)/5) help please
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solve for a
\[\frac{ a-1 }{ 8 }-\frac{ 3(a-4) }{ 10 }=\frac{ 2a+4 }{ 5 }\] Your denominators are 8, 10 and 5. What's the smallest number that is divisible by all 3 (lcd)?
80?
80's not the smallest, but it will still work :) You need to multiply each of the fractions by 80 so the denominators will cancel when you reduce. \[\frac{ 80(a-1) }{ 8 }-\frac{ (80)(3)(a-4) }{ 10 }=\frac{ 80(2a+4) }{ 5 }\]
i got 2.215
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as my final answer
that's not what I got. Can you put up what you did?
i got -65/23 is that right? @peachpi
??
no. the 23 is right, so everything you did with the a is good. check your addition/subtraction with the constants
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11?
yes
11/23
can u show me how you got that
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