Would anyone mind helping me to see if I did this correctly? At the city museum, child admission is $5.90 and adult admission is $9.00.On Sunday, three times as many adult tickets as child tickets were sold, for a total sales of $921.20.How many child tickets were sold that day? C+A=14.9 5.90C+9.00A=921.20 5.90(14.9-A)+9.00A=921.20 5.90-14.9=87.91 87.91-5.90+9.00A=921.20 -3.1A=833.29 CANCEL OUT THE -3.1 AND DIVIDE 833.29 BY -3.1A =268.80 SO WOULD IT BE A=268.80?
uh, not quite, remember that A = the number of adult tickets, so it should be a whole number (no decimals!) how about we start over from the very beginning, ok?
ok, we let C = number of child's tickets and A = number of adults tickets, with me so far?
there should be a decimal since it is money right?
think about what A and C represent...
A = number of adult tickets C = number of child tickets there's no such thing as a half a ticket, correct? the number of tickets must be a whole number
Um okay
well, the problem tells us that "three times as many adult tickets as child tickets were sold" which tells us that: A = 3*C, agreed?
Yes
and we know that (price of adult ticket)(number of adult tickets) + (price of child's ticket)(number of child's tickets) = total sales
alright
giving us: 5.90C + 9.00A = 921.20, correct?
Yes
so i had that part right
now let's work w/ our two equations: A = 3C 5.90C + 9.00A = 921.20
wait let me gues
5.90(3-a)+9.00a=921.20?
almost but not quite...
oh lol
A = 3C, so we can replace "A" with "3C" whenever A shows up
giving us: 5.90C + 9.00A = 921.20 5.90C + 9.00(3C) = 921.20
alright
now let's work on the left side of the equation... 5.90C + 9.00(3C) = 5.90C + 27C = 32.9C, agreed?
yes
so that leaves us with 32.9C = 921.20 do you know how to find C from here?
would I divide ?
yup, divide both sides by 32.9 to find C
I got an odd number...
check your math again, use a calculator if you aren't sure
921.20/32.9 = ?
0.0357142857142857
other way around, big number divided by small number 921.20/32.9 = ?
28
ooooo thank you
right, so C = 28, and since C is the number of child's tickets, 28 is our answer
thank you!
@Vocaloid mind helping me with another one it's my last question
sure, I'll give it a shot
post a new question and tag me
Join our real-time social learning platform and learn together with your friends!