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OpenStudy (anonymous):
I was able to figure out how to graph the \[f(x)=\sqrt{3x+2}\]
OpenStudy (anonymous):
but the f^-1 is new to me
OpenStudy (welshfella):
ok you need to find x in terms of f(x)
let f(x) = y
y = sqrt(3x + 2)
square borh sides
y^2 = 3x + 2
can you continue?
OpenStudy (anonymous):
now , from what @welshfella did, try making x the subject formula
OpenStudy (anonymous):
I feel so dumb right now, but I'm really trying to understand.
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OpenStudy (welshfella):
f-1(x) means the inverse of f(x)
find x in terms of y:-
3x = y^2 - 2
x = (y^2 - 2) / 3
now replace x by f-1(x) and y by x
f-1(x) = (x^2 - 2) / 3
OpenStudy (anonymous):
very correct @welshfella
OpenStudy (anonymous):
okay before I saw the answer at the bottom there I made up my mind that it had to be the third option I have in the picture, which I guess means I do understand it a little bit.
OpenStudy (anonymous):
Thanks so much @welshfella I'll have to keep reviewing this though
OpenStudy (welshfella):
yes and try a few examples
try a simple one ;-
f(x) = 4x
Find f-1(x)
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