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I was able to figure out how to graph the \[f(x)=\sqrt{3x+2}\]
but the f^-1 is new to me
ok you need to find x in terms of f(x) let f(x) = y y = sqrt(3x + 2) square borh sides y^2 = 3x + 2 can you continue?
now , from what @welshfella did, try making x the subject formula
I feel so dumb right now, but I'm really trying to understand.
f-1(x) means the inverse of f(x) find x in terms of y:- 3x = y^2 - 2 x = (y^2 - 2) / 3 now replace x by f-1(x) and y by x f-1(x) = (x^2 - 2) / 3
very correct @welshfella
okay before I saw the answer at the bottom there I made up my mind that it had to be the third option I have in the picture, which I guess means I do understand it a little bit.
Thanks so much @welshfella I'll have to keep reviewing this though
yes and try a few examples try a simple one ;- f(x) = 4x Find f-1(x)
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