A health food store has launched a new pack of vitamins for children. The store records the number of packs ordered by a random sample of 100 online customers and the number of packs ordered by a random sample of 100 walk-in customers.
Which of the following inferences can be drawn about the buying pattern of the online customers versus that of the walk-in customers? Online customers buy an average of five packs compared with walk-in customers, who buy an average of three packs. Online customers buy an average of five packs compared with walk-in customers, who buy an average of two packs. Online customers buy an average of six packs compared with walk-in customers, who buy an average of three packs. Online customers buy an average of six packs compared with walk-in customers, who buy an average of two packs.
@Michele_Laino @Vocaloid
Count the total number of packs bought by on-line customers and the same for walk-in. You can then find the average number of packs per customer by dividing the above totals by the number of customers
OK
Number packs for on-line customers = 5*6 + 4*5 + 4 = ?
54 @welshfella
the mean of online customers is: \[\Large \frac{{\left( {4 \cdot 1} \right) + \left( {5 \cdot 4} \right) + \left( {6 \cdot 5} \right)}}{{10}} = ...?\]
54 is right so divide that by 10 to get the mean for online customers
whereas the mean of walk-in customers is: \[\Large \frac{{\left( {3 \cdot 2} \right) + \left( {3 \cdot 6} \right) + \left( {4 \cdot 1} \right)}}{{10}} = ...?\]
28?
yes! and 28/10=...?
2.8
correct! which can be rounded off to 3
whereas the mean of online customers is 54/10=...?
5.4
correct! and it can be rounded off to 5
so, what is the right option?
A.
that's right!
thank you so much! :)
:)
Join our real-time social learning platform and learn together with your friends!