The function f(x)= cot(3x-pi/2) has ___.?
A. period pi/3 and asymptote at x=pi/6
B. period 2pi/3 and asymptote at x=pi/6
C. period 2pi/3 and asymptote at x=0
D. period pi/3 and asymptote at x=0
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jimthompson5910 (jim_thompson5910):
the period of the general cotangent function shown below is T = pi/B
y = A*cot(Bx - C) + D
jimthompson5910 (jim_thompson5910):
let me know if that's enough to get you started
OpenStudy (anonymous):
I still don't quiet understand
jimthompson5910 (jim_thompson5910):
do you see how the Bx and 3x match up?
OpenStudy (anonymous):
yeah
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jimthompson5910 (jim_thompson5910):
so B = 3 and you plug that into T = pi/B to get pi/3 as the period
OpenStudy (anonymous):
oh okay. And then how would I find the asymptote ?
jimthompson5910 (jim_thompson5910):
what happens when you plug in x = 0 ?
OpenStudy (anonymous):
you get 0?
jimthompson5910 (jim_thompson5910):
yes, so because x = 0 produces a single number as an output, this means x = 0 is NOT a vertical asymptote
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jimthompson5910 (jim_thompson5910):
that leaves x = pi/6 to be an asymptote
sure enough if you plug in x = pi/6, you should get NAN or UND or whatever error your calculator will spit out
OpenStudy (anonymous):
so it's not D?
jimthompson5910 (jim_thompson5910):
it's A actually
jimthompson5910 (jim_thompson5910):
yeah D is out because f(0) is defined
OpenStudy (anonymous):
Okay i understand thank you so much:)
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