The function f(x)= cot(3x-pi/2) has ___.? A. period pi/3 and asymptote at x=pi/6 B. period 2pi/3 and asymptote at x=pi/6 C. period 2pi/3 and asymptote at x=0 D. period pi/3 and asymptote at x=0
the period of the general cotangent function shown below is T = pi/B y = A*cot(Bx - C) + D
let me know if that's enough to get you started
I still don't quiet understand
do you see how the Bx and 3x match up?
yeah
so B = 3 and you plug that into T = pi/B to get pi/3 as the period
oh okay. And then how would I find the asymptote ?
what happens when you plug in x = 0 ?
you get 0?
yes, so because x = 0 produces a single number as an output, this means x = 0 is NOT a vertical asymptote
that leaves x = pi/6 to be an asymptote sure enough if you plug in x = pi/6, you should get NAN or UND or whatever error your calculator will spit out
so it's not D?
it's A actually
yeah D is out because f(0) is defined
Okay i understand thank you so much:)
glad to be of help
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