Question

Please help

Answer 1

@jim_thompson5910

Answer 2

HI!!

Answer 3

ready?

Answer 4

yes

Answer 5

first the \(-2\) outside means a) flip everything, then
b) square it

Answer 6

Okay

Answer 7

so first
\[\huge\frac{1}{\left(-3u^2v^3\right)^2}\]

Answer 8

then we need so square everything
that means square \(-3\) to get \(9\) and also double each exponent

Answer 9

Okay but where did the 2 come from in the parenthesis

Answer 10

\[\huge\frac{1}{\left(-3u^3v^3\right)^2}=\frac{1}{9u^6v^6}\]

Answer 11

oh oops that was a typo

Answer 12

Oh okay :) i'm following

Answer 13

should have been \[\huge\frac{1}{\left(-3u^3v^3\right)^2}\]

Answer 14

then square all
answer above is right though, looks like your choice A

Answer 15

thank you :) okay there is another question like it... can i post it and tell you how i would do it and then you tell me if i am doing it right or not??

Answer 16

ok sure \[\color\magenta\heartsuit\]

Answer 17

So i would flip it first right

Answer 18

no not here

Answer 19

the reason we flipped before was because there was a \(-2\) outside the parentheses

Answer 20

Oh okay so then i wouldn't flip it i would leave it the same

Answer 21

there is only one choice here that makes sense
take a look you have
\[\huge\frac{x^4}{x^{-5}}\] right?

Answer 22

the \(-5\) in the deominator means bring it up to the numerator as \(+5\) so
\[\frac{x^4}{x^{-5}}=x^4\times x^5=x^{4+5}=x^9\]

Answer 23

only one choice as \(x^9\) in it so we dont really need to do the rest

Answer 24

so i take the two common ones and add them

Answer 25

yeah you want to do it all?

Answer 26

Yes please cause i have a lot more questions like this and i want to make sure i understand them

Answer 27

ok lets take it slow

Answer 28

first off, unlike the last one there is no parentheses anywheres, so it is somewhat easier

Answer 29

you have a minus sign out front
that stays there

Answer 30

you also have \[\frac{2}{4}\] which is the same as \(\frac{1}{2}\) so there will be a 2 in the denominator

Answer 31

Okay

Answer 32

as for the x terms, you have \[\frac{x^4}{x^{-5}}\] the \(-5\) has a minus sign, so that comes upstairs as \(x^5\) which is why you get \[\frac{x^4}{x^{-5}}=x^4\times x^5=x^9\]

Answer 33

Alright

Answer 34

and for \[\frac{y^2}{y^5}\] the 5 is bigger than the 2, so subtract 2 from 5 in the denominator \[\frac{y^2}{y^5}=\frac{1}{y^{5-2}}=\frac{1}{y^3}\]

Answer 35

so in total,
a) there is a - sign out front
b) there is a 2 in the denominator
c) there is a \(x^9\) in the numerator and
d) a \(y^3\) in the denominator

Answer 36

Okay so which ever number is bigger you use that to decide whether or not you add or subtract and whether or not it says on the top or the bottom, am i right?

Answer 37

yes more or less

Answer 38

if the exponent is negative
a) if it is up bring it down
b) if it is down bring it up

Answer 39

if both terms have positive exponents, subtract the smaller one from the bigger one

Answer 40

here is an example
\[\frac{x^7}{x^{-3}}=x^{10}\] wheras
\[\frac{x^4}{x^{10}}=\frac{1}{x^6}\]

Answer 41

Okay that makes a little more since now

Answer 42

whew

Answer 43

Thanks