Question

(1/9)l5x-3l -3 ≥ 2 (Those l's are for absolute value. I am so confused. Anyone got a solution?)

Answer 1

Solve separately the expression |5x-3| as +(5x-3) and -(5x-3), which means you have two solutions.
solve
(1/9)(5x-3)\(\ge\)2 and
-(1/9)(5x-3)\(\ge\)2
to get the two required solutions.

Answer 2

I have to solve for x and I think I have to start with l5x-3l - 3 = 18

Answer 3

Yes, that's ok too!, now put the expression as 5x-3 and -(5x-3) and solve the equations.

Answer 4

but
(1/9)(5x-3)-3≥2 => (5x-3)-27≥18 and

-(1/9)(5x-3)-3≥2 => -(5x-3)-27≥18

Answer 5

ummm

Answer 6

Add 27 to both sides, we have
(5x-3)-27+27≥18+27
-(5x-3)-27+27≥18+27
or
5x-3≥45 and
-5x+3≥45
solve accordingly.