Question

8x2 + 64x = 0

Answer 1

I am guessling that is 8x^2... So, what problem are you having with it?

Answer 2

the answers choices are
x=0 ,x=-8
x=0,x=8
x=-8,x=0,x=8
x=8,x=64

Answer 3

@e.mccormick

Answer 4

Yes, and what is giving your trouble? This is a tutoring site...

Answer 5

i dont understand anything at all im lost can you explain ?

Answer 6

When you have something = 0 equations, you need to factor it and then find when the factors would be 0. This is sometimes called the roots, zeros, or x intercepts of a polynomial.

Answer 7

So, if you factor \(8x^2 + 64x\), what do you get?

Answer 8

8x^2

Answer 9

Um, that is the first term, but it is not the factors.

Answer 10

ok , so can you break this down in help me step by step ?

Answer 11

Well, do you know what factoring is?

Answer 12

not a clue

Answer 13

OK, if I say \(a\times b\times c\) then a, b and c are factors. They are multiplied together. Another common use is prime factorization. Like how 15 has the prime factors of 3 and 5.

So that polynomeal is the result of multiplying together something. When you un-multiply it, you are factoring it.

Answer 14

x^2 would be the factors ?

Answer 15

No, it would be something like \((x\pm h)(x\pm k)\) where h and k are some constants.

Answer 16

If I multiply out \((x+1)(x-3)\) I get:
\(x^2+x-3x-3\)
or:
\(x^2-2x-3\)

So \((x+1)\) and \((x-3)\) are factors of \(x^2-2x-3\). That is why factoring can be called un-multiplying.

Answer 17

ion know i just guessed

Answer 18

One big clue with this one is that each term has x in it. If you factor out the x, what would you get?

Answer 19

when someone is helping you, and they ask you a question and you guess, it makes them not want to hep you.

Answer 20

solve your equation step-by-step.
8x2+64x=0
Factor left side of equation.
8x(x+8)=0
Set factors equal to 0.
8x=0 or x+8=0

This should be more than enough clues :)