Question

Find the x-intercepts of the graph of the equation:
y = x^2 - 3x + 2
hmm so i got x=2, and x=1 which doesn't make sense

Answer 1

why ?

Answer 2

well when i plugged the numbers in it wasn't equivalent

Answer 3

\[2^2-3(2)+2=0 ? \\ \text{ well } 2^2-3(2)+2=4-6+2=-2+2=0 \\ \text{ so } 2^2-3(2)+2=0 \text{ is a true equation }\]

Answer 4

and you can check the other one in a similar way

Answer 5

you should get \[1^2-3(1)+2 \text{ is also } 0\]

Answer 6

oh wait so i got it right....

Answer 7

yes
the x-intercepts are (2,0) and (1,0)

Answer 8

you solved 0=x^2-3x+2 correctly

Answer 9

OMG!!!! proud moment :P

Answer 10

you did good! :)

Answer 11

thanks! :)