Question

Help me solve
2x^2+3x+4 ÷ x-2 .... please?

Answer 1

@freckles @uri @Hero

Answer 2

its 2x+7+(18/(x-2))

Answer 3

okay.. @dinamix so you end up with 2x^2+3x+4 all over x-2?

Answer 4

U should end up somewhat like (2x-a)(x-b)

Answer 5

so that is the answer? (2x-a)(x-b)?

Answer 6

but u cant find like that dude

Answer 7

The quadratic equation ax^2+bx+c

Answer 8

yup i know

Answer 9

U have to find a and b. They are the mystery numbers

Answer 10

But I used the numbers a=2, b=3, and c=4

Answer 11

Euclidean division its easy method dude

Answer 12

We know x-2 is one of them so we get (2x-a)(x-2)

Answer 13

Now,what times -2 equals 4?

Answer 14

you long or synthetic division

Answer 15

-2

Answer 16

dinamix had the answer

Answer 17

Right. So your answer would be (2x-2)(x-2)

Answer 18

hey guys all know Euclidean division , right ?

Answer 19

Now to check ur answer multiply the, together.

Answer 20

You get 2x*x+2x*2-2*x-2*-2

Answer 21

lol its 2x^2-6x+4

Answer 22

Simplify it and you get 2x^2+3x+4

Answer 23

woah woah woah, so the answer is "(2x-2)(x-2)

Answer 24

its 2x+7+(18/(x-2)) iam sure about it mate ;D trust me

Answer 25

Waiting my bad @dinamix is correct trust him m8

Answer 26

so I should put "2x+7+(18/(x-2))"

Answer 27

He used long division wit da thingys

Answer 28

Yes

Answer 29

Sry :3

Answer 30

its easy method euclidean division , study it right