Question

Write an equavilant expression that will enable you to indentify the zeros from the equation:
1. 8(x-3) + 5(x-3)=0
2. 4(x-2)^3(2x-4)+2(x-2)^4=0

Answer 1

Let me try to explain this as nicely as I can. In the quadratic \[8(x-3)+5(x-3)=0\] you can factorise it to become \[(8+5)(x-3)=0\] when the terms in the brackets (x-3) in this case are the same.

Answer 2

Then you can use null factor law to solve from there.

Answer 3

Do you follow so far?