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1+5(x-8)≤2-(x+5) ?
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You have to distribute first.
I got 1+5x-40≤2-(x+5)
Okay now distribute on the other side.
._. Doesn't 2 have to be by the parentheses for me to distribute?
You distribute the negative. So negative times x becomes -x
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Do you get it?
So would that be 1+5x-40≤2-x+5?
Kinda...
It would be negative 5 since you're multiplying by a negative
Okay, so 1+5-40≤2-x-5...
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Yes. Now combine like terms.
How do I do that if both X's are on opposite sides? ._. I apologize, I'm really bad in math.
It's fine. On the right side you can combine the 2 and -5
What did you get?
okay, 1+5x-40≤-x-3
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Now on the left side you can combine 1 and -40
5x-39≤-x-3
You're trying to get x by itself so you have to add x to both sides
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