Which of the following would be equivalent to 3^2 • 3^5? 3^10/3^3 3^10/3^7 3^1*3^7 3^0
when we divide same bases we should `subtract` their exponents \[\huge\rm \frac{ x^m }{ x^n }=x^{m-n}\] and when we `multiply` same bases we should `add` ther exponents \[\huge\rm x^m \times x^n=x^{m +n}\]
so would it be the third one?
from the answers?
3rd one is \[\huge\rm 3^1 \times 3^7\] ???
i know but i need the answer that is eqivelent to 3^2*3^5!
i said when we multiply same bases we should add their exponents so 3^2 times 3^5= ???
im not understanding it
here is an example \[\huge\rm 2^\color{ReD}{5} \times 2^\color{blue}{4} = 2^{\color{red}{5} +\color{blue}{4}} =2^9\]
so \[\huge\rm 3^\color{ReD}{2} \times 3^\color{blue}{5} = 3^{???}\]
3^7
yes right! now look at the options which option is equal to 3^7
the third option right?
here are some examples anything to the zero power is just equal to one \[\huge\rm (x)^0= 1~~~~(anything)^0=1\] and like i said when we divide same bases we should subtract their exponents example is \[\huge\rm \frac{ 2^5 }{ 2^3 }=2^{5-3}\]
\[3^1 \times 3^7=?\]would you add those exponents or subtract ?
subtract
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha when we divide same bases we should `subtract` their exponents \[\huge\rm \frac{ x^m }{ x^n }=x^{m-n}\] and when we `multiply` same bases we should `add` ther exponents \[\huge\rm x^m \times x^n=x^{m +n}\] \(\color{blue}{\text{End of Quote}}\) read this
ok we add
right so \[\huge\rm 3^1 \times 3^7= 3^{1+7} \] is this equal to 3^7 ??
3^8
so that's not equal to 3^7 that's why 3rs one isn't correct
3rd*
try other options
o it would be the first one because you subtract it and it would equal 3^7 right?
:=) nice!!!
thanks @Nnesha you helped me alot!!! :)
my pleasure :=)
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