Question

PLZ HELP?!?!?!?!(WILL MEDAL+FAN)
The functions p(x) and g(x) are shown below:

g(x) = 0.09x
p(x) = (0.09)x

Which statement best describes the graph of p(x) and g(x)?

A. The graphs will both have their y-intercept equal to 1.
B. The graphs will both have their y-intercept equal to 0.09.
C. The graph of p(x) will eventually exceed the graph of g(x).
D.The graph of g(x) will eventually exceed the graph of p(x).

Answer 1

i dont know how to to this..

Answer 2

Did you mean this?\[g(x)=0.09x\\
p(x)=0.09^x\]

Answer 3

it says
g(x) = 0.09x
p(x) = (0.09)x

Answer 4

i think its either a or b

Answer 5

ab is the same as a(b)

I'm kind of thinking you meant what @amilapsn wrote above

Answer 6

yeah they do mean the same thing

Answer 7

\[\\ p(x)=0.09^x \text{ this is the same as } \\ p(x)=(0.09)^x \\ \text{ if you have happen to have ( )} \\ \text{ in your problem and you don't know what they mean }\]
so did @amilapsn interpret your problem correctly

Answer 8

yes, i agree it can be written p(x)=0.09^x

Answer 9

ok so great we are in agreement (0.09)x is not the same as (0.09)^x correct?

Answer 10

anyways do you know how to graph the line and the exponential function ?

Answer 11

no

Answer 12

A. The graphs will both have their y-intercept equal to 1.
can we answer this question then?
to find the y-intercept set x=0 and find y.
\[\\ \text{ for } g \text{ we have } y=0.09(0)=? \\ \text{ for } p \text{ we have } y=0.09^0=?\]
are the y-intercepts the same?

Answer 13

Yes they both equal 1
oh i was over thinking it all i had to do was solve for y
Thank you, ur a life saver

Answer 14

no

Answer 15

0.09 times 0 is 0

Answer 16

0.09 to the 0 power is 1

Answer 17

they are not both the same so choice A is definitely not the answer
let's look at choice B

Answer 18

B. The graphs will both have their y-intercept equal to 0.09.
we know this is false too because we already found the y-intercepts previously

Answer 19

so the next thing to do is see which function eventually exceeds the other

Answer 20

and it would be kinda helpful to graph/draw the functions