Question

Studying for a test and don't remember how to do this.

Write the standard equation of the circle with center (-3, 5) and a diameter of 14.

(x + 3)2 + (y – 5)2 = 49

(x + 3)2 + (y – 5)2 = 7

(x – 5)2 + (y + 3)2 = 49

(x – 3)2 + (y + 5)2 = 196

Answer 1

@Hero @dan815 @Nnesha @e.mccormick

Answer 2

\[\huge\rm (x-h)^2+(y-k)^2=r^2\]
standard form equation of the circle
where (h,k) is the center and r=radius
remember radius is half of diameter

Answer 3

So is it B?

Answer 4

if diameter is 14 then radius would be ?

Answer 5

7

Answer 6

\[\huge\rm (x-h)^2+(y-k)^2=r^\color{Red}{2}\]
yes right so now look at the equation it's r^squared

Answer 7

So it would be 49

Answer 8

yes right

Answer 9

So it would be A?

Answer 10

@Nnesha

Answer 11

i think so.:=)

Answer 12

Thank you so much!!(: