How do you find cos(11pi/6)?
HI!!
you need a good trig cheat sheet !
hint: we have: \[\Large \frac{{11\pi }}{6} = 2\pi - \frac{\pi }{6}\]
so we can write: \[\Large \cos \left( {\frac{{11\pi }}{6}} \right) = \cos \left( {2\pi - \frac{\pi }{6}} \right)\]
find \(\frac{11\pi}{6}\) on the unit circle on the the last page of the cheat sheet, then look at the coordinates of the corresponding point the first coordinate is cosine
Thanks guys
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What if you need to find tangent?
you can apply this identity: \[\Large \begin{gathered} \tan \left( {\frac{{11\pi }}{6}} \right) = \tan \left( {2\pi - \frac{\pi }{6}} \right) = \hfill \\ \hfill \\ = \frac{{\tan \left( {2\pi } \right) - \tan \left( {\frac{\pi }{6}} \right)}}{{1 + \tan \left( {2\pi } \right)\tan \left( {\frac{\pi }{6}} \right)}} \hfill \\ \end{gathered} \]
How do you know tan(11pi/6) equals tan(2pi-pi/6)?
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