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Mathematics 17 Online
OpenStudy (anonymous):

so i got a math question for ya

OpenStudy (anonymous):

wht is it

OpenStudy (anonymous):

I may be able to help. What is your question?

OpenStudy (anonymous):

In the equation x^2+3x-10=(x+g)(x+h) g and h are both intergers there are 2 possiable intergers for g wht are they

OpenStudy (anonymous):

b and a

OpenStudy (anonymous):

no g and h but only g im looking for

OpenStudy (anonymous):

oh

OpenStudy (welshfella):

first expand the RHS

OpenStudy (anonymous):

RHS?

OpenStudy (welshfella):

x^2+3x-10=(x+g)(x+h) x^2 + 3x - 10 = x^2 + gx + hx + gh

OpenStudy (welshfella):

right hand side

OpenStudy (welshfella):

x^2 + 3x - 10 = x^2 + gx + hx + gh x^2 + 3x - 10 = x^2 + (g + h)x + gh

OpenStudy (anonymous):

o ok

OpenStudy (welshfella):

now compare coefficients of x and x^0 g + h = 4 gh = -10

OpenStudy (welshfella):

now solve this system of equations to give you the values of g and h

OpenStudy (anonymous):

but i only need g

OpenStudy (welshfella):

oh sorry I don't know why i put 4 it should be 3 g + h = 3 gh = -10

OpenStudy (welshfella):

well find h in terms of g from first equation then plug it into the second

OpenStudy (welshfella):

from first equation h = 3 - g now sub in second g(3 - g) = -10 now solve this for g its a quadratic and you'll get 2 solutions

OpenStudy (anonymous):

thx

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

nope

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