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Mathematics
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OpenStudy (anonymous):
so i got a math question for ya
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OpenStudy (anonymous):
wht is it
OpenStudy (anonymous):
I may be able to help. What is your question?
OpenStudy (anonymous):
In the equation x^2+3x-10=(x+g)(x+h)
g and h are both intergers there are 2 possiable intergers for g wht are they
OpenStudy (anonymous):
b and a
OpenStudy (anonymous):
no g and h but only g im looking for
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OpenStudy (anonymous):
oh
OpenStudy (welshfella):
first expand the RHS
OpenStudy (anonymous):
RHS?
OpenStudy (welshfella):
x^2+3x-10=(x+g)(x+h)
x^2 + 3x - 10 = x^2 + gx + hx + gh
OpenStudy (welshfella):
right hand side
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OpenStudy (welshfella):
x^2 + 3x - 10 = x^2 + gx + hx + gh
x^2 + 3x - 10 = x^2 + (g + h)x + gh
OpenStudy (anonymous):
o ok
OpenStudy (welshfella):
now compare coefficients of x and x^0
g + h = 4
gh = -10
OpenStudy (welshfella):
now solve this system of equations to give you the values of g and h
OpenStudy (anonymous):
but i only need g
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OpenStudy (welshfella):
oh sorry I don't know why i put 4 it should be 3
g + h = 3
gh = -10
OpenStudy (welshfella):
well find h in terms of g from first equation then plug it into the second
OpenStudy (welshfella):
from first equation
h = 3 - g
now sub in second
g(3 - g) = -10
now solve this for g
its a quadratic and you'll get 2 solutions
OpenStudy (anonymous):
thx
OpenStudy (anonymous):
nope
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OpenStudy (anonymous):
nope
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