Question

integral from 0 to 3 5x Sin (3x+1)

I'm pretty sure this is an integration by parts. I made U 5x and dv = sin (3x+1). Is this the correct path?

Answer 1

\[\int\limits_{0}^{3} 5x \sin(3x+1)dx\] like this?

Answer 2

yes by parts would do it

Answer 3

By parts should work, u = 5x, dv = sin(3x+1) so now integrate for v

Answer 4

Note: \[\int\limits u dv = uv - \int\limits v du \]

Answer 5

so would v end up being \[\frac{ 1 }{ 3 } \sin (3x+1) \]

sorry for the dumb question. Been a couple of years since Calculus 1!

Answer 6

oops, change that sin to a -cos.

Answer 7

Yup

Answer 8

-1/3cos(3x+1)

Answer 9

Keep going, I'm sure you'll get it!