Question

Solve x3 = 64 over 27.
±8 over 3
8 over 3
±4 over 3
4 over 3

Answer 1

@dan815 @Nnesha

Answer 2

take cube root both sides to cancel out the cube

Answer 3

how

Answer 4

here is an example \[\huge\rm \sqrt[3]{m^3} = \sqrt[3]{27}\]

Answer 5

O.o

Answer 6

im confuzzled

Answer 7

you can convert root to exponent
cube root of m^3 is same as \[\huge\rm m^{3 \times \frac{ 1 }{ 3 }}\]
then you can cancel out the 3's \[\huge\rm m^{\cancel{3} \times \frac{ 1 }{ \cancel{3 }}}=m\]
that's how you can take cube root both sides to cancel out cube

Answer 8

take cube root both sides !

Answer 9

*cries*

Answer 10

idk how

Answer 11

\[\huge\rm \sqrt[3]{x^3}=\sqrt[3]{\frac{ 64 }{ 27 }}\]
that's how we should take cube root
cube= 3

Answer 12

\[\huge\rm \sqrt[3]{\frac{ a }{ b }}=\frac{ \sqrt[3]{a} }{ \sqrt[3]{b} }\]

Answer 13

take cube root of the numerator and take cube root of the denominator !