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Find the distance from the line y=2x+2 and the point 4,-6
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@phi @Michele_Laino @e.mccormick @nincompoop
so i know you put 4,-6 into point slope form which is y+6=-2(x-4)
then convert to slope incercept form which i think is y=-1/2x-4
@SithsAndGiggles
NVM I GOT IT
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2x-y+2=0 distance of (x1,y1)from ax+by+c=0 is\[d=\left| \frac{ ax1+by1+c }{ \sqrt{a^2+b^2} } \right|\]
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