TRIGONOMETRY:
Start with sin2(θ) + cos2(θ) = 1. What would you multiply through by to get sec2(θ) = tan2(θ) + 1?
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OpenStudy (dumbsearch2):
Nnesha (nnesha):
what is reciprocal of tan ?
OpenStudy (danjs):
sorry, i was still on the closed first question of this
OpenStudy (dumbsearch2):
cotangent @nnesha
OpenStudy (dumbsearch2):
So is the answer D?
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OpenStudy (danjs):
try each answer out to see if it will work...
Nnesha (nnesha):
not just cot
it should be 1/cot
but how would you write tan in terms of sin cos ?
OpenStudy (danjs):
you just need to know the basic definitions of the trig functions, and multiply through each anser to test if it works
OpenStudy (danjs):
For example in using A) 1/cos^2(x)
multiplying the given equation by that results in
\[\frac{ \sin^2(x) }{ \cos^2(x) }+\frac{ \cos^2(x) }{ \cos^2(x) } = \frac{ 1 }{ \cos^2(x) }\]
OpenStudy (danjs):
see if that is the same as the equation they are looking for
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OpenStudy (dumbsearch2):
I get tan^2(x), not sec.
OpenStudy (danjs):
right, sin^2 / cos^2 = tan^2 for the first fraction
OpenStudy (danjs):
do that for all 3
OpenStudy (danjs):
cos^2 / cos^2 = 1
OpenStudy (danjs):
and
1 / cos^2(x) = sec(x)^2
right
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OpenStudy (dumbsearch2):
So the answer is A?
OpenStudy (danjs):
it appears so, because you get
tan^2(x) + 1 = sec^2(x)
OpenStudy (danjs):
memorize the 6 trig vunctions and how they relate... tha tis all this is