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Mathematics 16 Online
OpenStudy (dumbsearch2):

TRIGONOMETRY: Start with sin2(θ) + cos2(θ) = 1. What would you multiply through by to get sec2(θ) = tan2(θ) + 1?

OpenStudy (dumbsearch2):

Nnesha (nnesha):

what is reciprocal of tan ?

OpenStudy (danjs):

sorry, i was still on the closed first question of this

OpenStudy (dumbsearch2):

cotangent @nnesha

OpenStudy (dumbsearch2):

So is the answer D?

OpenStudy (danjs):

try each answer out to see if it will work...

Nnesha (nnesha):

not just cot it should be 1/cot but how would you write tan in terms of sin cos ?

OpenStudy (danjs):

you just need to know the basic definitions of the trig functions, and multiply through each anser to test if it works

OpenStudy (danjs):

For example in using A) 1/cos^2(x) multiplying the given equation by that results in \[\frac{ \sin^2(x) }{ \cos^2(x) }+\frac{ \cos^2(x) }{ \cos^2(x) } = \frac{ 1 }{ \cos^2(x) }\]

OpenStudy (danjs):

see if that is the same as the equation they are looking for

OpenStudy (dumbsearch2):

I get tan^2(x), not sec.

OpenStudy (danjs):

right, sin^2 / cos^2 = tan^2 for the first fraction

OpenStudy (danjs):

do that for all 3

OpenStudy (danjs):

cos^2 / cos^2 = 1

OpenStudy (danjs):

and 1 / cos^2(x) = sec(x)^2 right

OpenStudy (dumbsearch2):

So the answer is A?

OpenStudy (danjs):

it appears so, because you get tan^2(x) + 1 = sec^2(x)

OpenStudy (danjs):

memorize the 6 trig vunctions and how they relate... tha tis all this is

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