Need help with subtracting rational expression with unlike denominators.
Please post your question
\[\frac{ 4a-2 }{ 3a+12 } - \frac{ a-2 }{ a+4 }\]
Hi, do I multiple the denominators to the opposite fraction of the numerator and denominator?
Since you need a common denominator, you would have to multiply the first term (top and bottom ) by a+4...With this in mind what do you think you will then need to multiply the second term by (top and bottom)?
\[\frac{ (a+4)(4a-2) }{ (a+4)(3a+12) } - \frac{ (3a+12)(a-2) }{ (3a+12)(a+4) }\]
Great now you can simplify. Do you know how?
\[\frac{ (a+4)(4a-2) - (3a+12)(a-2) }{ (3a+12)(a+4) }\]
Do I distribute by foiling?
u bet.
:D
Does the denominator stay that way (3a+12)(a+4)
yes
Thank you
you are welcome!
above is correct but whenever you can work with the lowest terms
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