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Mathematics 10 Online
OpenStudy (destinyyyy):

Need two problems checked...

OpenStudy (destinyyyy):

Solve the absolute value inequality. 36< {-2x+18/5} +9/5 {} absolute value

OpenStudy (destinyyyy):

180/5 <{-2x+ 18/5} -2x+18/5> 180/5 -2x+ 18/5< -180/5

OpenStudy (destinyyyy):

I got-- x> -81/5 x< 99/5

OpenStudy (linn99123):

okay so whats ur answer for number 1?

OpenStudy (destinyyyy):

I posted both of my answers above.

OpenStudy (destinyyyy):

Im not sure what you mean by number one. I only posted one question.

OpenStudy (danjs):

looks like you know the way to solve them, not sure about the numbers

OpenStudy (dinamix):

and i am sure about my answer

OpenStudy (destinyyyy):

Okay

OpenStudy (xapproachesinfinity):

\(|-2x+18/5|+9/5>36 \) \(|-2x+18/5|>189/5 \leftarrow \text{one correction here}\)

OpenStudy (destinyyyy):

Where are you getting 189 from???

OpenStudy (danjs):

36 - (9/5) = 171/5 for the first thing

OpenStudy (xapproachesinfinity):

36+9/5=189/5

OpenStudy (destinyyyy):

Omg... 36 *5= 180 .. I forgot to minus the 9 -.-

OpenStudy (xapproachesinfinity):

eh should be 180-9 i added them

OpenStudy (xapproachesinfinity):

it is ok well make mistakes

OpenStudy (xapproachesinfinity):

we all*

OpenStudy (xapproachesinfinity):

but the she got the point

OpenStudy (destinyyyy):

Now I have -2x> 153/5 -2x < -153/5

OpenStudy (xapproachesinfinity):

yah yo got the point of this just made some few error just recheck for certainty

OpenStudy (xapproachesinfinity):

you know how this works that's what is important

OpenStudy (xapproachesinfinity):

i got the same result you should be good to go

OpenStudy (destinyyyy):

Okay. But now im stuck.. -2 cant be divided into these. And my last problem like this just divided the top number by -2

OpenStudy (xapproachesinfinity):

multiply by -1/2 and switch the sign > to < and < to >

OpenStudy (xapproachesinfinity):

if you multiply by negative you should change the inequality

OpenStudy (destinyyyy):

Uh? I know what the final answer is because I looked it up on mathway... But dont get how I go from what I have to it.

OpenStudy (dinamix):

@Destinyyyy u have find it 171/10< x<-153/10 i didnt focus first time

OpenStudy (destinyyyy):

The answer is (- infinity sign, -153/10) u (189/10 , infinity sign)

OpenStudy (dinamix):

yup i was wrong its 189/10 sorry

OpenStudy (dinamix):

i forget add 18/2 only sorry

OpenStudy (destinyyyy):

How do I get from -2x> 153/5 and -2x< -153/5 to the final answer

OpenStudy (xapproachesinfinity):

i told you to multiply by -1/2 both sides

OpenStudy (xapproachesinfinity):

first one x<-153/10 see the inequality changed

OpenStudy (xapproachesinfinity):

second x>153/10

OpenStudy (dinamix):

not that u have -2x>153/5 ------ 2x<-153/5 -----x<-153/10 @Destinyyyy

OpenStudy (xapproachesinfinity):

actually you made a mistake somewhere for the scond

OpenStudy (dinamix):

i fix it now

OpenStudy (xapproachesinfinity):

it should not be -2x<-153/5

OpenStudy (dinamix):

this is not - its just Arrow

OpenStudy (destinyyyy):

Then Id have to change the denominators to 10... 306/10 5/10 .. Do I minus, divide, multiple?

OpenStudy (destinyyyy):

What are you talking about? Its over 5 not 10

OpenStudy (dinamix):

not that u have (-2x>153/5) ------ (2x<-153/5) -----(x<-153/10 ) @xapproachesinfinity this what i mean

OpenStudy (xapproachesinfinity):

the second should have been -2x<-189/5 then x>189/10

OpenStudy (xapproachesinfinity):

that what i meant she made a mistake in calculations

OpenStudy (xapproachesinfinity):

after that just read what x<-153/10 and x>189/10 mean in interval nottion

OpenStudy (xapproachesinfinity):

you should get that same answer you have by mathway

OpenStudy (xapproachesinfinity):

over 10 my bad

OpenStudy (destinyyyy):

OMG. Seriously. Im an still at -2x> 153/5 and -2x< -153/5

OpenStudy (destinyyyy):

I dont understand your multiple by -1/2.

OpenStudy (xapproachesinfinity):

you need to isolate x right

OpenStudy (xapproachesinfinity):

so we multiply by a minus sign which switches the inequality then we multiply by 1/2 to get rid of 2

OpenStudy (xapproachesinfinity):

it is like you do with equation to islote the unknown

OpenStudy (destinyyyy):

...

OpenStudy (destinyyyy):

Still dont understand.

OpenStudy (xapproachesinfinity):

how would you solve 2x=4

OpenStudy (destinyyyy):

Divide both sides by 2.

OpenStudy (xapproachesinfinity):

so same thing divide the inequality both sides by 2

OpenStudy (xapproachesinfinity):

that is the same as multiplying out by 1/2 hahaha

OpenStudy (destinyyyy):

Okay. Like I said before its not possible. It gives a decimal.... K? So then Id have to change both denominators to 10.

OpenStudy (xapproachesinfinity):

why decimal ? you get -153/5x2

OpenStudy (xapproachesinfinity):

i dont see where do you get decimal?

OpenStudy (destinyyyy):

What are you talking about? 153 divided by -2= -76.5

OpenStudy (xapproachesinfinity):

why you need to divide? leave it 153/5x2=153/10

OpenStudy (dinamix):

\[|-2x+\frac{ 18 }{ 2 }|>\frac{ 171 }{ 5 }\] \[\frac{ -171}{ 5 }>-2x+\frac{ 18 }{ 2 }>\frac{ 171 }{ 5}\] \[\frac{ -171-18 }{ 5 }>-2x>\frac{ 171-18 }{ 5}\] \[\frac{ -189 }{ 5}>-2x>\frac{ 153 }{ 5 }\] \[-\frac{ 153 }{ 10 }>x>\frac{ 189 }{ 10 }\] @xapproachesinfinity could u check my mistake @Destinyyyy this is real solution

OpenStudy (xapproachesinfinity):

you making this hard on youself

OpenStudy (dinamix):

cuz i think this is right answer @xapproachesinfinity

OpenStudy (destinyyyy):

No im not. You are making this impossible to understand. Ive waited 2 hours for help and now Im just confused. Normally you just divide it. And instead im suppose to multiple it. But all you did was change the denominator. Why???

OpenStudy (xapproachesinfinity):

yes your answer is good @dinamix

OpenStudy (destinyyyy):

You said to multiply by 1/2 so I asked about changing both denominator to 10. And both times you did not respond. So im just suppose to do 5*2= 10 ?

OpenStudy (xapproachesinfinity):

heheheh thanks i thought i made efforts to show you

OpenStudy (destinyyyy):

I understand the first one. Now what about the other one.

OpenStudy (dinamix):

@xapproachesinfinity ty @Destinyyyy what u didnt understand we can help u

OpenStudy (xapproachesinfinity):

ok dinamix take over i have to go

OpenStudy (dinamix):

@xapproachesinfinity plz i dont know how to explain

OpenStudy (destinyyyy):

Try showing me?

OpenStudy (dinamix):

its hard to expalin idea for me @xapproachesinfinity this problem of me

OpenStudy (dinamix):

@Destinyyyy what i show u

OpenStudy (destinyyyy):

Can you just show me how you went from -2x< -153/5 to 189/10

OpenStudy (dinamix):

-2x>153/5 to x<-153/10 right ?

OpenStudy (dinamix):

that what u mean or what

OpenStudy (destinyyyy):

If I go off from what both of you said before by just multiplying by -1/2 then Ill just get 153/10 which is not the correct answer. Which also makes me think how you said to solve the first one is not the correct way to solve it.

OpenStudy (destinyyyy):

The fist sign goes < not >

OpenStudy (destinyyyy):

-2x< -153/5 to 189/10

OpenStudy (dinamix):

\[-2x+\frac{ 18 }{ 5} > 171/5\] and \[-(-2x+\frac{ 18 }{ 5 })>171/5 \]\[\frac{ -171 }{ 5 } >-2x+\frac{ 18 }{ 5 }>\frac{ 171 }{ 5}\]

OpenStudy (dinamix):

@Destinyyyy its 2 equation i make it only one did u understand now

OpenStudy (freckles):

36< |-2x+18/5| +9/5 Just because I like to write the absolute value expression first then the inequality thingy.. \[|-2x+\frac{18}{5}|+\frac{9}{5}>36 \\ \text{ so you subtracted } \frac{9}{5} \text{ on both sides } \\ |-2x+\frac{18}{5}|>36-\frac{9}{5} \\ |-2x+\frac{18}{5}|> \frac{180-9}{5} \\ |-2x+\frac{18}{5}| >\frac{171}{5} \\ \text{ now since this is a greater than we have a union } \\ \text{ that is we have } -2x+\frac{18}{5}<-\frac{171}{5} \text{ or } -2x+\frac{18}{5}>\frac{171}{5} \\ \text{ for both inequalities subtract }\frac{18}{5} \text{ on both sides } \\ -2x<\frac{-171}{5}-\frac{18}{5} \text{ or } -2x> \frac{171}{5}-\frac{18}{5} \\ \text{ simplifying right hand sides } \\ -2x <\frac{-189}{5} \text{ or } -2x >\frac{153}{5} \\ \text{ now you can say divide both sides by -2 } \\ \text{ or equivalently say multiply both sides by } \frac{-1}{2} \\ \text{ this is the same meaning just different saying } \] \[\frac{-1}{2} \cdot (-2x)>\frac{-1}{2}(\frac{-189}{5}) \text{ change direction of inequality symbol } \\ \text{ since I multiplied both sides by a negative } \\ x>\frac{189}{10} \\ \text{ now the other inequality } \\ \frac{-1}{2}(-2x)<\frac{-1}{2}(\frac{153}{5}) \\ x<\frac{-153}{10}\] so put the two pieces together and put or between them

OpenStudy (dinamix):

@freckles like my steps lol

OpenStudy (freckles):

\[x<\frac{-153}{10} \text{ or } x>\frac{189}{10}\]

OpenStudy (freckles):

your solution seems to suggest -171 is greater than 171 since it says -171/5>171/5 @dinamix

OpenStudy (dinamix):

@freckles but why we get same result

OpenStudy (freckles):

no I didn't get -171>171 because this is not true

OpenStudy (destinyyyy):

Omg thank you @freckles I completely understood everything you said. And I saw where I messed up. I did write down the - for -171/5 so when I minus-ed the 18 I had the wrong answer. Now I have the correct one and understand how to solve the ending.

OpenStudy (dinamix):

but @freckles look the last i get -153/10 >x or x>189/10 look

OpenStudy (destinyyyy):

And all that turns into (- infinity sign, -153/10) u (189/10, infinity sign)

OpenStudy (destinyyyy):

@freckles Can you check one more? I know that my answer is wrong, but im not sure how it is.

OpenStudy (freckles):

alright one more and then I eat

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