Question

Let g(x)=2x and h(x)=x^2+4. Find the value.
(h o g) (1) How do you do this?

Answer 1

first) substitute x for 1 into g(x) function :D

Answer 2

(h o g) meaning find \[\huge\rm h(\color{red}{g(1)})\]

Answer 3

Oh ok

Answer 4

\[\huge\rm g(\color{reD}{1})=2\color{ReD}{x}\]
replace x with 1

Answer 5

On the other side as well or only on the left?

Answer 6

\(\bf {\color{brown}{ g(x) }}=2x\qquad h(x)=x^2+4\qquad

(h\circ g)(x) \iff h(\ {\color{brown}{ g(x)}}\ )
\\ \quad \\
h(\ {\color{brown}{ g(x)}}\ )={\color{brown}{ g(x)}}^2+4\implies h(\ {\color{brown}{ g(x)}}\ )={\color{brown}{ (2x)}}^2+4\)

Answer 7

Ah ok

Answer 8

And then do I keep simplifying to get a final number?

Answer 9

well right side
g(x) is same as y

Answer 10

Thank you