Question

Suppose there are 15 jelly beans in a box (2 red, 3 blue, 4 white, and 6 green). A jelly bean is selected at random.

What is the probability that the jelly bean is neither red nor blue?

Answer 1

total : 15
take out the red and blue
how many jellybeans would you have left ?

Answer 2

10

Answer 3

\[\frac{ 15-(\color{ReD}{2}+\color{blue}{3}) }{ 15 }\]
yes right!

Answer 4

so would it be 10/15 = 2/3 in lowest terms?

Answer 5

yes right!

Answer 6

thank you! very helpful

Answer 7

np :=)