I am getting the wrong answers and I don't know where I am going wrong! Please help! 4. The line with the equation 5x+y=20 meets the x axis at A and the line with the equation x+2y=22 meets the y axis at B. The two lines intersect at point C. (iv) Find the co-ordinates of the point E such that ABEC is a parallelogram. This is what I have done (I don't know if this is right or not): I have found the gradient of BA ( -11/4) which I know will be parallel to EC. I then use the point (0,11) to find the equation of the line BA. I get 4y+11x=44 from this. I do the same for CA (parallel to EB) .
It wouldnt let me type any more so heres the rest
I get -5 for the gradient and use point C (2,10) to get the equation of the line 5x+y=20
I solve the two equations simultaneously to find where they intersect and only get through the first part till I get -9x=56 which I already know is wrong since x has to equal -2
I can post a picture of everything too
The first line: 5x +y =20 (1), A on this line and A (4,0) The second line : x+2y = 22 (2) , B on this line and B (0,11) Ok??
Yes
|dw:1441547331269:dw|
C (2,10) ok?
Ok.
now, if it forms a parallelogram, then the left side is |dw:1441547541029:dw|
Oh wait i think you have A and B wrong.
|dw:1441547556565:dw|
Show me my mistake, please.
This is the answer for the first question it asked saying what the graph looks like
So B is on the line on the bottom and is is on the line to the left
yes, just estimate. As long as my logic is Ok, I am ok.
Ok :)
|dw:1441547716564:dw|
agree with me for this?
Yes, I think so
|dw:1441547741256:dw| That is I need a line parallel to 5x+y =20 and passes through B, right?
Now, calculate that line by plugging B coordinate in the equation, I get \(5\color{red}{x}+\color{blue}{y}=20\\5\color{red}{0}+\color{blue}{11}=11\), Hence my new line has the equation 5x +y =11|dw:1441547933249:dw|
Join our real-time social learning platform and learn together with your friends!