Find the area of the segment of circle C shown above.(below) http://media.education2020.com/evresources/2092518_e27bdadc-5042-4dc8-a271-bd47449d4779.png
will give medal!
A. a segment=353.66 u^2 B. a segment=434.88 u^2 C. a segment=458.88 u^2 D. a segment=707.32 u^2
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@Nnesha
you can do the area of that entire 120 degree region and then take away the area of that 120 degree triangle probably
The answer would be A
Are you still working on this, or no, sorry just got back here
The area of a circle is pi*radius^2, the area of the pie slice angle 120 is \[\pi*24^2*\frac{ 120 }{ 360 } = 192\pi \approx 603.19\] The triangle TCS has area \[144\sqrt{3} \approx 249.42\]
subtracting the two, the shaded area is 603.19-249.24 = 353.77
\[Area: A=\left(\begin{matrix}1 \\ 2\end{matrix}\right)r ^{2}(\alpha-\sin \alpha)\left[ 1 \right]\]
thak you.
sorry i had to leave for a few minutes. duty calls. :)
i have one more question
?
find S which is the length of arc WV on circle C http://media.education2020.com/evresources/2092520_c,jpg.jpg
is 0=7/9pi the degrees?
A. s=7/2 pi B. s=7pi C. s=14pi D. s=28pi
is not 0 its theta
i think the formula is S= THETA/180 *PI*RADIUS
arc length = radius * angle \[s=r*\theta \]
so would it be 18*7/9*pi
yep
oh so it would be 14pi
lol sorry this shouldnt have been a quiestion to ask. whoops. I can be so areless sometimes. But thank you to all of you that helped. I really appriciate it!:)
welcome
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