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lim x approaching 1 (x^2-1)/(x^2-x)
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factor factor!
x^2-1 is a difference of squares and x^2-x you have each term having a common factor of x
still dont know what to do
do you know how to factor x^2-1?
x^2-a^2=(x-a)(x+a) and you have a=1 so x^2-1=?
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0
x^2-1 is not always 0
x^2-1=(x-1)(x+1) just using the formula I gave you above
x^2-x=x(x-1)
\[\lim_{x \rightarrow 1} \frac{x^2-1}{x^2-x}=\lim_{x \rightarrow 1} \frac{(x-1)(x+1)}{x(x-1)}\] you see anything that cancels?
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wow okay i wrote it wrong , thanks
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