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whats z^2z^4/z^3Z^-1
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\[z ^{2} z ^{4}/z ^{3}z ^{-1}\]
\[z^2z^4/z^3z ^{-1}= z^1/z^3 = 1/z^2\]
u study number complexe
how did you get z^1 on the top and z^3 on the bottom?
@dinamix
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isn't it 2+4 which is 6 and the 3+ (-1)=2
z^4/z^3 = Z^(4-3) = Z^1
how're you getting those numbers though
and z^2/z^-1 = z^(2-(-1)) =z^3
ohhh okay i see what you did there! this problem was so easy but it wars confusing for second thanks for your help
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its when u see Basis of divided like this u have make difference
\[z^x * z^y = z ^{x+y}\]
\[z^x/z^y = z^{x-y}\]
@Anzhbar
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