Question

x^2+4x-5/1-x

Answer 1

Please Help

Answer 2

ok wait

Answer 3

is the answer given?

Answer 4

@ajmaine

Answer 5

Try and factoring the numerator

Answer 6

see you got to middle term breaking the numerator

Answer 7

x^2+4x-5
x^+5x-x-5
x(x+5)-1(x+5)
(x-1)(x+5)

Answer 8

then it becomes(x-1)(x-5)/1-x

Answer 9

Please allow the poster to do some work @madhu.mukherjee.946

Answer 10

so now take -1 common
-1(1-x)(x+5)/1-x
both the 1-x terms cancel
so it becomes -x-5=0
sox=-5

Answer 11

I dont understand anything so far, also I have to go offline. Sorry see ya guys

Answer 12

omg

Answer 13

you don't know middle term breaking