Question

Find x3 - 2y2 - 3x3 + z4 if x = 3, y = 5, and z = -3.

Answer 1

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Answer 2

x^3 - 2y^2 - 3x^3 + z^4 ---- x = 3, y = 5, z = -3
now we sub
3^3 - 2(5^2) - 3(3^3) + (-3^4)
can you do the math now ?

Answer 3

-185

Answer 4

27 - 2(25) - 3(27) + 81
27 - 50 - 81 - 81
-212 + 27
-185
thats what I got

Answer 5

oops..made a mistake on first line...supposed to be -81

Answer 6

yep

Answer 7

same answer....-185

Answer 8

so it is -185

Answer 9

yes

Answer 10

i got it wrong

Answer 11

hold on...let me check again
3^3 - 2(5^2) - 3(27) + 81 ---- it is + 81 because -3^4 = -3*-3*-3*-3 = 81
27 - 50 - 81 + 81
- 23 (the 81's cancel each other out)

Answer 12

I am so sorry about that

Answer 13

can i ask you another question

Answer 14

??

Answer 15

Find -3a2 - b3 + 3c2 - 2b3 if a = 2, b = -1, and c = 3.