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Algebra 15 Online
OpenStudy (inspectorjoe):

what times # = -20 but when added =- 7?

Nnesha (nnesha):

what are the factors of 20 ?

OpenStudy (inspectorjoe):

factors of -20.. I know -5X4 but when I add it does not =-7

Nnesha (nnesha):

yes right and when u multiply -2 times -5 you will get 20 but not -20 so `none` are solving quadratic equation ?

OpenStudy (inspectorjoe):

no. here is my problem 3y^2+7y-20= factors

Nnesha (nnesha):

i knew it! leading coefficient isn't one so u should multiply AC

Nnesha (nnesha):

so first multiply 3 times -20 then find two numbers

OpenStudy (inspectorjoe):

oh great yes I got thanks

OpenStudy (anonymous):

|dw:1441759651765:dw|

OpenStudy (anonymous):

congrats

Nnesha (nnesha):

remeber for AC method find two numbers when you multiply them you should get product of AC(a=leading coefficient , c=constant)

OpenStudy (inspectorjoe):

i came up with -17

Nnesha (nnesha):

and do you know you can't write the answer like (x+1st number) (x+2nd number)

Nnesha (nnesha):

what do you mean `-17`?

OpenStudy (inspectorjoe):

I took 3 X -20 to come up with my needed number

Nnesha (nnesha):

oh no i meant first multiply 3 times -20= which is equal to -60 now find two numbers when you multiply them you should get -60 but when you add or subtract them you should get -7

Nnesha (nnesha):

+7**

OpenStudy (inspectorjoe):

:O(?

Nnesha (nnesha):

??

Nnesha (nnesha):

if leading coefficient is one then we still have to multiply A times C but as u know when you multiply by one you will get the same thing but here leading coefficinet is 3 so multiply a times c = 3 times -20 then find two numbers

OpenStudy (inspectorjoe):

right great thanks

Nnesha (nnesha):

np :=)

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