A standard deck of 52 playing cards has 4 suits with 13 different cards in each suit. How many different five-card hands are possible?
A)
260 hands
B)
2,598,960 hands
C)
24,380 hands
D)
311,875,200 hands

Question

A standard deck of 52 playing cards has 4 suits with 13 different cards in each suit. How many different five-card hands are possible?
A)
260 hands	
B)
2,598,960 hands	
C)
24,380 hands	
D)
311,875,200 hands

anonymous · Answer

what..

anonymous · Answer

52 choose 5
52 C 5
$\large  52 \choose 5 $

anonymous · Answer

these are different ways to represent the same thing

mertsj · Answer

How many choices for the first card?

anonymous · Answer

Are you allowed to use a calculator

anonymous · Answer

yea

anonymous · Answer

Using a calculator is kind of cheap. 
Mertsj do you have a different approach

anonymous · Answer

you could always use wolfram and type in 
52 choose 5

mertsj · Answer

Yes.  There are 52 choices for the first card.
There are 51 choices for the second card.
There are 50 choices for the third card.
There are 49 choices for the fourth card.
There are 48 choices for the fifth card.
So total possible hands are:
52 x 51 x 50 x 49 x 48 = 311,875,200

anonymous · Answer

thats an overestimate

anonymous · Answer

the order does not count when you receive the 5 cards

anonymous · Answer

is it d?

anonymous · Answer

its b

mertsj · Answer

It is D

anonymous · Answer

example
2H 3H 4H 5H 6H = 3H 2H 4H 5H 6H = ... 
the order does not count, so you divide by 5!

mertsj · Answer

Oh yes.  The order of selection doesn't matter so divide by 5 x 4 x 3 x 2 x 1

mertsj · Answer

B

anonymous · Answer

thanks