Can someone help me with a few questions??! I have issues with slope!
Can you post one of the questions.
What is the slope of the line that passes through the given points? (3,2) and (5,12) a. 5 b. -5 c. -1/5 d. 1/5
The slope of the line through points (x1,y1) and (x2,y2) is given by : \(\huge m=\frac{y_1-y_2}{x_1-x_2}\) now,just put the values and find m.
in your question, x1= 3 y1 = 2 x2 =5 y2 =12
so 2-12/3-5
yes don't forget the brackets (2-12)/(3-5)
-10/-2=5
good! \(\huge \checkmark\)
Can you help with some more?
sure :)
What is the graph of the equation? 2x-y=2
it would be a line. to get the intercepts of that line plug in x= 0, find y plug in y= 0 find x
How do I plug it in? Sorry I am lost..
2x- y =2 to get x intercept, we put y =0 2x = 2 x =1 so x intercept is 1,0 can you now find y intercept ? put x= 0 in 2x-y =2
y=0
-y = 2 so y =-2 y intercept is 0,-2
now the points 1,0 and 0,-2 should lie on the graph. which graph has these 2 points?
C
correct :)
Write an equation of the line, in point slope form that passes through the two given points: (-2,15) and (9,-18) a.y-2=-3(x-15) b.y-2=-1/3(x+15) c.y-15=-3(x+2) d.y-15=-1/3(x+2)
first find the slope using the above formula. x1 = -2 y1 = 15 x2 = 9 y2 = -18
-11/33=3
-11/33 is -1/3
Oh yeah sorry..
so the equation would be y-y1 = m (x-x1) y -15 = -1/3 (x+2)
Thank you! I have 8 more can you help? I am starting to understand!
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