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Mathematics 20 Online
OpenStudy (anonymous):

3y^5-75y^3

OpenStudy (welshfella):

if you want to factor this you need to find the GCF

OpenStudy (welshfella):

find GCF of 3 and 75 and GCF of y^3 and y^5

OpenStudy (anonymous):

y and idk

OpenStudy (welshfella):

what number divides exactly into 3 and 75?

OpenStudy (welshfella):

- that is the GCF

OpenStudy (anonymous):

1

OpenStudy (welshfella):

yes 1 does but its not the greatest factor that divides into 3 and 75

OpenStudy (anonymous):

3

OpenStudy (welshfella):

right the GCF is 3 what about y^3 and y^5 ?

OpenStudy (welshfella):

y will but its not the greatest factor

OpenStudy (anonymous):

y^3

OpenStudy (welshfella):

right! so GCF is 3y^3

OpenStudy (welshfella):

now you need to divide 3y^3 into 3y5 - 75y^3 to find what goes into the parentheses

OpenStudy (anonymous):

3y^3(y^2-25y)

OpenStudy (welshfella):

i'll do the first part for you 3y^5 / 3y^3 = y^(5-3) = y^2

OpenStudy (welshfella):

you are almost right but 75 y^3 / 3y^3 = 25 not 25y

OpenStudy (anonymous):

oh k

OpenStudy (welshfella):

correct is 3y^3(y^2 - 25)

OpenStudy (anonymous):

now what do we do

OpenStudy (welshfella):

pretty good job

OpenStudy (welshfella):

that is it we have factored it

OpenStudy (anonymous):

k thanks

OpenStudy (welshfella):

oops sorry y6 - 25 can be factored also - nearly missed that

OpenStudy (welshfella):

y^2 - 25 is the difference of 2 squares y^2 and 25 are exact squares square root of y^2 is y and square root of 25 is 5 right?

OpenStudy (anonymous):

right

OpenStudy (welshfella):

so the factors are 2 binomials with square roots in eachh and + in one binomial and - in the other y^2 - 25 = ( y + 5)(y - 5)

OpenStudy (anonymous):

thanks that was a close call

OpenStudy (welshfella):

finally 3y^5-75y^3 = 3y^3(x + 5)(x - 5)

OpenStudy (anonymous):

thanks that was a close call

OpenStudy (welshfella):

yea - watch out for those lol

OpenStudy (welshfella):

- i should have put y's not x's I guess I'm tired

OpenStudy (welshfella):

3y^5-75y^3 = 3y^3(y + 5)(y - 5)

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