Mathematics
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OpenStudy (anonymous):
3y^5-75y^3
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OpenStudy (welshfella):
if you want to factor this you need to find the GCF
OpenStudy (welshfella):
find GCF of 3 and 75
and GCF of y^3 and y^5
OpenStudy (anonymous):
y and idk
OpenStudy (welshfella):
what number divides exactly into 3 and 75?
OpenStudy (welshfella):
- that is the GCF
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OpenStudy (anonymous):
1
OpenStudy (welshfella):
yes 1 does but its not the greatest factor that divides into 3 and 75
OpenStudy (anonymous):
3
OpenStudy (welshfella):
right the GCF is 3
what about y^3 and y^5 ?
OpenStudy (welshfella):
y will but its not the greatest factor
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OpenStudy (anonymous):
y^3
OpenStudy (welshfella):
right!
so GCF is 3y^3
OpenStudy (welshfella):
now you need to divide 3y^3 into 3y5 - 75y^3 to find what goes into the parentheses
OpenStudy (anonymous):
3y^3(y^2-25y)
OpenStudy (welshfella):
i'll do the first part for you
3y^5 / 3y^3 = y^(5-3) = y^2
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OpenStudy (welshfella):
you are almost right but 75 y^3 / 3y^3 = 25 not 25y
OpenStudy (anonymous):
oh k
OpenStudy (welshfella):
correct is
3y^3(y^2 - 25)
OpenStudy (anonymous):
now what do we do
OpenStudy (welshfella):
pretty good job
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OpenStudy (welshfella):
that is it
we have factored it
OpenStudy (anonymous):
k thanks
OpenStudy (welshfella):
oops sorry
y6 - 25 can be factored also - nearly missed that
OpenStudy (welshfella):
y^2 - 25 is the difference of 2 squares
y^2 and 25 are exact squares
square root of y^2 is y and square root of 25 is 5 right?
OpenStudy (anonymous):
right
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OpenStudy (welshfella):
so the factors are 2 binomials with square roots in eachh and + in one binomial and - in the other
y^2 - 25 = ( y + 5)(y - 5)
OpenStudy (anonymous):
thanks that was a close call
OpenStudy (welshfella):
finally
3y^5-75y^3 = 3y^3(x + 5)(x - 5)
OpenStudy (anonymous):
thanks that was a close call
OpenStudy (welshfella):
yea - watch out for those lol
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OpenStudy (welshfella):
- i should have put y's not x's I guess I'm tired
OpenStudy (welshfella):
3y^5-75y^3 = 3y^3(y + 5)(y - 5)