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Mathematics 20 Online
OpenStudy (cutiecomittee123):

A 50 foot tree asts its shadow 75 feet long. How can you find sine for the angle of elevation determined by the sun and the top of the tree?

OpenStudy (anonymous):

what grade u in ??

OpenStudy (here_to_help15):

@*ImaBeMe* I find that irrelevant,if your not going to help please hit that log out option and annoy someone else.

jimthompson5910 (jim_thompson5910):

hint: |dw:1441844647460:dw| solve for \(\Large \theta\)

OpenStudy (cutiecomittee123):

I agree please leave if you arent willling to help I am trying to keep my schedule organized and I actually am in need of help. this is not a dating website.

OpenStudy (here_to_help15):

@ganeshie8 @jim_thompson5910

jimthompson5910 (jim_thompson5910):

another hint: |dw:1441844715344:dw|

OpenStudy (anonymous):

ok i just asked dang

OpenStudy (cutiecomittee123):

this is precalculus incase youre wondering.

jimthompson5910 (jim_thompson5910):

if you aren't familiar with the trig ratios, this chart may help http://passyworldofmathematics.com/Images/pwmImagesSix/TrigRatiosSix550x389JPG.jpg

OpenStudy (cutiecomittee123):

alright so sinfeta=50/x

OpenStudy (cutiecomittee123):

then take the inverse right?

OpenStudy (cutiecomittee123):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

theta = \(\Large \theta\) it's a greek letter

OpenStudy (cutiecomittee123):

Oh gotcha

jimthompson5910 (jim_thompson5910):

which two sides are known to us? (pick between opposite, adjacent, hypotenuse)

OpenStudy (cutiecomittee123):

we know opposite and adjacent. which are opposite=50 and adjacent=75

jimthompson5910 (jim_thompson5910):

yep, which trig function uses opposite and adjacent?

OpenStudy (cutiecomittee123):

but it is asking to find sine

jimthompson5910 (jim_thompson5910):

oh I see, I was thinking they just wanted theta, nvm

jimthompson5910 (jim_thompson5910):

ok so you'll need the hypotenuse first because sin(theta) = opp/hyp

OpenStudy (here_to_help15):

Wait up i remember this in Geometry, are you sure it isnt Geometry

jimthompson5910 (jim_thompson5910):

so use the pythagorean theorem to find x |dw:1441845085421:dw| a^2 + b^2 = c^2 50^2 + 75^2 = x^2 x = ???

OpenStudy (cutiecomittee123):

you do learn this in geometry, if you want to try and give it a shot, i wont stop you lol

OpenStudy (cutiecomittee123):

c=90.14

OpenStudy (cutiecomittee123):

sintheta=50/90.14

jimthompson5910 (jim_thompson5910):

you have one more step to go

OpenStudy (cutiecomittee123):

uhh that is where i need help

OpenStudy (cutiecomittee123):

dont you just take the inverse

jimthompson5910 (jim_thompson5910):

use a calculator to compute 50/90.14

OpenStudy (cutiecomittee123):

okay i got .5546

jimthompson5910 (jim_thompson5910):

I'm getting 50/90.14 = 0.55469270024407 which rounds to 0.5547

OpenStudy (cutiecomittee123):

yes!

OpenStudy (cutiecomittee123):

and that is what the angle sin is equal to right?

jimthompson5910 (jim_thompson5910):

that decimal value is equal to \(\Large \sin(\theta)\), yes

OpenStudy (cutiecomittee123):

okay cool, and that is it right?

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