Question

Find the non-extraneous solutions of the square root of the quantity x plus 6 minus 5 equals quantity x plus 1.

x = −2
x = −6 and x = −5
x = −6 and x = −2
x = 2

Answer 1

@Hero
@pooja195
@Nnesha

Answer 2

\[\huge\rm \sqrt{x+6}-5=x+1\]like this ?

Answer 3

ya

Answer 4

first we need to get rid of `-5` from left side so move -5 to the right side
how would you do that ?
would you add ,subtract ,multiply or divide ?

Answer 5

add

Answer 6

yes right add 5 both sides

Answer 7

what did you get ?

Answer 8

6

Answer 9

yes right so \[\sqrt{x+6}=x+6\]
now take square both sides to cancel out the square root \[\huge\rm (\sqrt{x+6})^2= (x+6)^2\]

Answer 10

square root and square cancel each other out
you will get x+6 at left side
now foil (X+6)^2
(X+6)^2 is same as (x+6)(x+6) multiply

Answer 11

sorry my internet is being slow

Answer 12

it's okay take ur time :=)

Answer 13

x^2+36

Answer 14

no that's not right
there is a plus sign so you should get 3 terms

Answer 15

multiply top two terms with the left side write ur answer in the box