Question

For each quadratic relation, determine the y-intercept and the axis of symmetry
a) y= x^2 + 2
b) y= -x^2 -4

Answer 1

For part A) I got y=2 because I set x to 0 to get my y-intercept
y=x^2+2
y=0^2+2
y=2 (0,2)

Answer 2

I then set my y-int to 0 to get my x
y=x^2+2
0=x^2+2
0=1x+2
x=2 (2,0)

Answer 3

Am I doing it right so far?
How do i find the axis of symmetry?