Identify an equation in standard form for an ellipse with its center at the origin, a vertex at (0, 12), and a focus at (0, 8).
It appears that it's a horizontal ellipse so I know that the equation will be \[\frac{ x ^{2} }{ a ^{2} } + \frac{ y ^{2} }{ b ^{2} }=1\]
That is right.
I just don't know how to find the other vertex in order to find b^2.
Actually isn't it a verticle ellipse.
Because the vertex (furtherest point) is 12 up from the origin
Oh yes, that's right!
So the semi major axis is 12, in the y direction
Therefore the equation is (y^2)/(12^2) + (x^2)/(b^2) = 1
Now for the b value I think you use the rule that for any point on the ellipse, the sum of the distance from both foci is 2a (a is the semi major axis)
Ill draw a graph to show
So, you use the constant sum of an ellipse formula: d=PF1 + PF2
|dw:1441973292765:dw| in the picture i took the point to be the semi minor axis. Since the ellipse is symmertrical (both foci same distance) the distance from that point to each foci is a (semi major axis)
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