Question

I only have two questions left in my homework that's due tonight before midnight and I need help with them.

Prove the statement using the ε, δ definition of a limit.
lim x^2 = 0
x→0
Given ε > 0, we need δ > 0 such that if 0 < |x − 0| <  δ, then |x^2 − 0| <  ε ⇔ (blank) <  ε ⇔ |x|< (blank). Take δ = (blank). Then 0 < |x − 0| <  δ right double arrow implies |x^2 − 0| < ε. Thus, lim x^2 = 0 by the definition of a limit.
x→0

Use the given graph of f to find a number δ such that if
|x − 1| < δ then |f(x) − 1| < 0.2 δ = (Blank)
Graph: http://www.webassign.net/scalcet7/2-4-001.gif