1+1 Real question in comments
I have the answer I just don't know how to work it out.\[\frac{ 1 }{ 2 }(b-3)=\frac{ 5 }{ 2}\]
\[b = \frac{ 4 }{ 0.5 } \]
o.o..
But\[\frac{ 4 }{ 0.5 }=8\] in simplest form
@Teddyiswatshecallsme
whats the answer ?
@Nnesha 8
\(\color{blue}{\text{Originally Posted by}}\) @I_love_my_nieces I have the answer I just don't know how to work it out.\[\frac{ 1 }{ 2 }(b-3)=\frac{ 5 }{ 2}\] \(\color{blue}{\text{End of Quote}}\) how would you get rid of the 2 at left side would you add , subtract multiply or divide ?
The 2 at what end?
@Nnesha
multiply 2 both sides to get rid of 2
Where do you see a 2?
\[\frac{ 1 }{ \color{ReD}{2} }(b-3)=\frac{ 5 }{ 2}\]
that's 2 ^^
we have to solve for b right ? so we need to move all the numbers which is at left side to the right side
so that's why multiply both sides by 2 to cancel out the red two at left side \[\frac{ 1 }{ \color{ReD}{2} }(b-3)=\frac{ 5 }{ 2}\]
SO multiply 1/2 by 2? and 5/2 by 2?
yes right!
1 and 5
yes right so \[\huge\rm 1(b-3)=5 ~~~~~~~~b-3=5\] now can you solve for b ?
brb stay right here
o_0 i hve 2 mints XD
knock knock i'm leaving ..... :D
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha yes right so \[\huge\rm 1(b-3)=5 ~~~~~~~~b-3=5\] now can you solve for b ? \(\color{blue}{\text{End of Quote}}\) after this move the -3 to the right side sorry i have to go
if you have question about this please ask Luigi0210 :D
@Luigi0210
got it ?
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