Question

SOLVE FOR T: 6P=Pe^(1.4t)

Answer 1

first we need to get rid of p at right side

Answer 2

how would you cancel out p from right side ?

Answer 3

do you know ? yes or no ?

Answer 4

No, I don't know

Answer 5

@Nnesha

Answer 6

it's p `times` e^P(1.4t)
so to cancel out p from right side do opposite of `multiplication `

Answer 7

Divide by P on both sides to cancel P?

Answer 8

yes right

Answer 9

\[\huge\rm \frac{ 6p }{ p}=\frac{ pe^{(1.4t)} }{ p }\] what do you get ?

Answer 10

6=e^(1.4t)

Answer 11

yes right not take natural log both sides to cancel out the e \[\huge\rm \cancel{ln e}^a = a\]bec ln and e cancel each other out

Answer 12

t= 1.2798 ?

Answer 13

hm no how did you get that

Answer 14

oh wait

Answer 15

ln of 6 divided by 1.4? is that wrong?

Answer 16

yes that's right

Answer 17

Yay!!!

Answer 18

Yahoo!!! good job!

Answer 19

thanks so much!

Answer 20

yw :=)